\(\int \frac {(d x)^m}{a+b x^3+c x^6} \, dx\) [250]

Optimal result

Integrand size = 20, antiderivative size = 173 \[ \int \frac {(d x)^m}{a+b x^3+c x^6} \, dx=\frac {2 c (d x)^{1+m} \operatorname {Hypergeometric2F1}\left (1,\frac {1+m}{3},\frac {4+m}{3},-\frac {2 c x^3}{b-\sqrt {b^2-4 a c}}\right )}{\sqrt {b^2-4 a c} \left (b-\sqrt {b^2-4 a c}\right ) d (1+m)}-\frac {2 c (d x)^{1+m} \operatorname {Hypergeometric2F1}\left (1,\frac {1+m}{3},\frac {4+m}{3},-\frac {2 c x^3}{b+\sqrt {b^2-4 a c}}\right )}{\sqrt {b^2-4 a c} \left (b+\sqrt {b^2-4 a c}\right ) d (1+m)} \]

[Out]

2*c*(d*x)^(1+m)*hypergeom([1, 1/3+1/3*m],[4/3+1/3*m],-2*c*x^3/(b-(-4*a*c+b^2)^(1/2)))/d/(1+m)/(b-(-4*a*c+b^2)^
(1/2))/(-4*a*c+b^2)^(1/2)-2*c*(d*x)^(1+m)*hypergeom([1, 1/3+1/3*m],[4/3+1/3*m],-2*c*x^3/(b+(-4*a*c+b^2)^(1/2))
)/d/(1+m)/(-4*a*c+b^2)^(1/2)/(b+(-4*a*c+b^2)^(1/2))

Rubi [A] (verified)

Time = 0.16 (sec) , antiderivative size = 173, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {1389, 371} \[ \int \frac {(d x)^m}{a+b x^3+c x^6} \, dx=\frac {2 c (d x)^{m+1} \operatorname {Hypergeometric2F1}\left (1,\frac {m+1}{3},\frac {m+4}{3},-\frac {2 c x^3}{b-\sqrt {b^2-4 a c}}\right )}{d (m+1) \sqrt {b^2-4 a c} \left (b-\sqrt {b^2-4 a c}\right )}-\frac {2 c (d x)^{m+1} \operatorname {Hypergeometric2F1}\left (1,\frac {m+1}{3},\frac {m+4}{3},-\frac {2 c x^3}{b+\sqrt {b^2-4 a c}}\right )}{d (m+1) \sqrt {b^2-4 a c} \left (\sqrt {b^2-4 a c}+b\right )} \]

[In]

Int[(d*x)^m/(a + b*x^3 + c*x^6),x]

[Out]

(2*c*(d*x)^(1 + m)*Hypergeometric2F1[1, (1 + m)/3, (4 + m)/3, (-2*c*x^3)/(b - Sqrt[b^2 - 4*a*c])])/(Sqrt[b^2 -
4*a*c]*(b - Sqrt[b^2 - 4*a*c])*d*(1 + m)) - (2*c*(d*x)^(1 + m)*Hypergeometric2F1[1, (1 + m)/3, (4 + m)/3, (-2
*c*x^3)/(b + Sqrt[b^2 - 4*a*c])])/(Sqrt[b^2 - 4*a*c]*(b + Sqrt[b^2 - 4*a*c])*d*(1 + m))

Rule 371

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^p*((c*x)^(m + 1)/(c*(m + 1)))*Hyperg
eometric2F1[-p, (m + 1)/n, (m + 1)/n + 1, (-b)*(x^n/a)], x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
(ILtQ[p, 0] || GtQ[a, 0])

Rule 1389

Int[((d_.)*(x_))^(m_.)/((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_)), x_Symbol] :> With[{q = Rt[b^2 - 4*a*c, 2]
}, Dist[c/q, Int[(d*x)^m/(b/2 - q/2 + c*x^n), x], x] - Dist[c/q, Int[(d*x)^m/(b/2 + q/2 + c*x^n), x], x]] /; F
reeQ[{a, b, c, d, m}, x] && EqQ[n2, 2*n] && NeQ[b^2 - 4*a*c, 0] && IGtQ[n, 0]

Rubi steps \begin{align*} \text {integral}& = \frac {c \int \frac {(d x)^m}{\frac {b}{2}-\frac {1}{2} \sqrt {b^2-4 a c}+c x^3} \, dx}{\sqrt {b^2-4 a c}}-\frac {c \int \frac {(d x)^m}{\frac {b}{2}+\frac {1}{2} \sqrt {b^2-4 a c}+c x^3} \, dx}{\sqrt {b^2-4 a c}} \\ & = \frac {2 c (d x)^{1+m} \, _2F_1\left (1,\frac {1+m}{3};\frac {4+m}{3};-\frac {2 c x^3}{b-\sqrt {b^2-4 a c}}\right )}{\sqrt {b^2-4 a c} \left (b-\sqrt {b^2-4 a c}\right ) d (1+m)}-\frac {2 c (d x)^{1+m} \, _2F_1\left (1,\frac {1+m}{3};\frac {4+m}{3};-\frac {2 c x^3}{b+\sqrt {b^2-4 a c}}\right )}{\sqrt {b^2-4 a c} \left (b+\sqrt {b^2-4 a c}\right ) d (1+m)} \\ \end{align*}

Mathematica [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 9 vs. order 5 in optimal.

Time = 0.25 (sec) , antiderivative size = 84, normalized size of antiderivative = 0.49 \[ \int \frac {(d x)^m}{a+b x^3+c x^6} \, dx=\frac {(d x)^m \text {RootSum}\left [a+b \text {$\#$1}^3+c \text {$\#$1}^6\&,\frac {\operatorname {Hypergeometric2F1}\left (-m,-m,1-m,-\frac {\text {$\#$1}}{x-\text {$\#$1}}\right ) \left (\frac {x}{x-\text {$\#$1}}\right )^{-m}}{b \text {$\#$1}^2+2 c \text {$\#$1}^5}\&\right ]}{3 m} \]

[In]

Integrate[(d*x)^m/(a + b*x^3 + c*x^6),x]

[Out]

((d*x)^m*RootSum[a + b*#1^3 + c*#1^6 & , Hypergeometric2F1[-m, -m, 1 - m, -(#1/(x - #1))]/((x/(x - #1))^m*(b*#
1^2 + 2*c*#1^5)) & ])/(3*m)

Maple [F]

\[\int \frac {\left (d x \right )^{m}}{c \,x^{6}+b \,x^{3}+a}d x\]

[In]

int((d*x)^m/(c*x^6+b*x^3+a),x)

[Out]

int((d*x)^m/(c*x^6+b*x^3+a),x)

Fricas [F]

\[ \int \frac {(d x)^m}{a+b x^3+c x^6} \, dx=\int { \frac {\left (d x\right )^{m}}{c x^{6} + b x^{3} + a} \,d x } \]

[In]

integrate((d*x)^m/(c*x^6+b*x^3+a),x, algorithm="fricas")

[Out]

integral((d*x)^m/(c*x^6 + b*x^3 + a), x)

Sympy [F(-1)]

Timed out. \[ \int \frac {(d x)^m}{a+b x^3+c x^6} \, dx=\text {Timed out} \]

[In]

integrate((d*x)**m/(c*x**6+b*x**3+a),x)

[Out]

Timed out

Maxima [F]

\[ \int \frac {(d x)^m}{a+b x^3+c x^6} \, dx=\int { \frac {\left (d x\right )^{m}}{c x^{6} + b x^{3} + a} \,d x } \]

[In]

integrate((d*x)^m/(c*x^6+b*x^3+a),x, algorithm="maxima")

[Out]

integrate((d*x)^m/(c*x^6 + b*x^3 + a), x)

Giac [F]

\[ \int \frac {(d x)^m}{a+b x^3+c x^6} \, dx=\int { \frac {\left (d x\right )^{m}}{c x^{6} + b x^{3} + a} \,d x } \]

[In]

integrate((d*x)^m/(c*x^6+b*x^3+a),x, algorithm="giac")

[Out]

integrate((d*x)^m/(c*x^6 + b*x^3 + a), x)

Mupad [F(-1)]

Timed out. \[ \int \frac {(d x)^m}{a+b x^3+c x^6} \, dx=\int \frac {{\left (d\,x\right )}^m}{c\,x^6+b\,x^3+a} \,d x \]

[In]

int((d*x)^m/(a + b*x^3 + c*x^6),x)

[Out]

int((d*x)^m/(a + b*x^3 + c*x^6), x)